2(x+2)^2-4=68

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Solution for 2(x+2)^2-4=68 equation: 



2(x+2)^2-4=68

We move all terms to the left:

2(x+2)^2-4-(68)=0

We add all the numbers together, and all the variables

2(x+2)^2-72=0

We move all terms containing x to the left, all other terms to the right

2(x+2)^2=72

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